The frequencies of R is 0.75 and the frequencies for R' is 0.25.
Explanation:
Data given:
Genotype frequency of incomplete dominance on flower colour of snapdragon:
RR = red 0.5625
RR' = Pink 0.375
R'R' = 0.0625
frequency of R and R'=?
According to Hardy-Weinberg equilibrium the genetic variation in a given population is constant from one generation to other if no factors causing evolution or genetic drift is there. So,
[tex]p^{2}[/tex] + [tex]q^{2}[/tex]+ 2pq = 1
The p represents = homozygous dominant RR
q represents = homozygous recessive R'R'
2pq = frequency of heterpzygous genotype RR'
[tex]p^{2}[/tex] = 0.5625
p = 0.75 (frequency of R)
[tex]q^{2}[/tex] = 0.0625
q = 0.25 (Frequency of R')
Their sum is 1 as according to Hardy Weinberg condition:
p+q = 1