If angles are complementary then their sum is 90 degrees.
[tex]\alpha+\beta=90^{\circ}[/tex].
If one is twice the other we get,
[tex]2\beta + \beta=3\beta=90^{\circ}\implies \beta=\frac{90^{\circ}}{3}=\boxed{30^{\circ}}[/tex]
And,
[tex]\alpha+30^{\circ}=90^{\circ}\implies\alpha=90^{\circ}-30^{\circ}=\boxed{60^{\circ}}[/tex].
So the answer is A. 30 and 60.
Hope this helps.
