Answer: [tex]0.517\°[/tex]
Explanation:
According to Snell’s Law we have the following:
[tex]n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})[/tex] (1)
Where:
[tex]n_{1}=1[/tex] is the first medium index of refraction (air)
[tex]n_{2}=1.33[/tex] is the second medium index of refraction (water)
[tex]\theta_{1}=42.3\°[/tex] is the angle of the incident ray
[tex]\theta_{2}[/tex] is the angle of the refracted ray
So, we need to find from (1):
[tex]\theta_{2}=sin^{-1}(\frac{n_{1}}{n_{2}}sin\theta_{1})[/tex] (2)
[tex]\theta_{2}=sin^{-1}(\frac{1}{1.3}sin(42.3\°))[/tex] (3)
Finally:
[tex]\theta_{2}=0.517\°[/tex] This is the angle of refraction
