just need help with c, f, & e
please provide a step by step explanation
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Good morning
Answer:
Step-by-step explanation:
c.
[tex]f(x) =2 \\\\then\\\\\frac{x+2}{x-11} =2\\\\then\\\\x+2 = 2(x-11)\\\\then\\\\x+2=2x-22\\\\then\\\\x=24[/tex]
then the point (24 , 2) is on the graph.
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e.
[tex]f(x) =0 \\\\then\\\\\frac{x+2}{x-11} =0\\\\then\\\\x+2 = 0\\\\then\\\\x=-2[/tex]
Then the x-intercept is (-2 , 0)
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f.
f(0) = (0+2)/(0-11) = 2/(-11) = -2/11
then the y-intercept is (0 , -2/11)
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:)