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A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at the 30 cm mark. What is the weight of the meter stick?

Respuesta :

tochjosh

Answer:

The weight of the meter rule is equal to the weight W placed at the 30cm mark

Explanation:

Detailed explanation and calculation is shown in the image

Ver imagen tochjosh
Cricetus

The weight of the meter stick will be "W".

According to the question,

  • Distance of W to pivot= 10 cm
  • Distance of F to pivot = 10 cm

Let,

  • The weight of meter rule be "F".

We know,

→ [tex]Moment \ of \ a \ force = Force\times distance[/tex]

                       [tex]F \times 10 = W\times 10[/tex]

                              [tex]F = W[/tex]

Thus the answer above is right.

Learn more about fulcrum here:

https://brainly.com/question/14553436

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