Respuesta :
Answer:
There will be 262 frogs in 5 years
Step-by-step explanation:
The population of Marshville can be modeled by the following equation.
[tex]P(t) = P(0)(1 - r)^{t}[/tex]
In which P(t) is the population after t years, P(0) is the initial population, and r is how much the population decreases by year.
In this problem, we have that:
[tex]P(0) = 900, r = 0.2[/tex]
So
[tex]P(t) = 800(0.8)^{t}[/tex]
How many frogs will there be in 5 years?
This is P(5)
[tex]P(5) = 800(0.8)^{5} = 262[/tex]
There will be 262 frogs in 5 years
Answer:
295 frogs
Step-by-step explanation:
The Population of Marshville is loosing 20% of their population of frogs per year.
This means the value of the next year is 80% of the previous year.
This is an example of a geometric series in which the common ratio =80%
The nth term of a geometric series is given as:
[tex]U_n=ar^{n-1}[/tex]
Where a=First Term, r=Common Ratio, n=Number of Terms
In this case.
a=900, r=80%=0.8, n=6 (After 5 years)
[tex]U_5=900*0.8^{6-1}\\=900*0.8^{5}=294.9 \approx 295[/tex]
In 5 years time, there will be 295 frogs in Marshville.
