Answer:[tex]\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }[/tex]
Step-by-step explanation:
[tex]c=24x^2 pi[/tex]
Switch sides:
[tex]24x^2\pi =Kc[/tex]
divide both sides by [tex]24\pi[/tex]
[tex]\frac{24x^2\pi }{24\pi }=\frac{Kc}{24\pi }[/tex]
simplify:
[tex]x^2=\frac{Kc}{24\pi }[/tex]
[tex]x^2=\frac{Kc}{24\pi }[/tex][tex]x=\sqrt{\frac{Kc}{24\pi }},\:x=-\sqrt{\frac{Kc}{24\pi }}[/tex]
answer:[tex]x=\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }[/tex]
i hope it's help!
