The difference of measures between the arcs subtended by chord AB is 160°. Line l is tangent to the circle at point A. Find the measure of the angle between the tangent l and secant AB.
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Given:
Given that the difference of measures between the arcs subtended by chord AB is 160°.
Line l is tangent to the circle at point A.
We need to determine the measure of the angle between the tangent l and secant AB.
Measure of arc AB:
Let x denote the measure of minor arc AB.
Thus, we have;
[tex]x+(x+160^{\circ})=360^{\circ}[/tex]
[tex]2x+160^{\circ}=360^{\circ}[/tex]
[tex]2x=200^{\circ}[/tex]
[tex]x=100^{\circ}[/tex]
Thus, the measure of the minor arc AB is 100°
Measure of angle between the tangent l and the secant AB:
Since, we know the property that, "if a tangent and the chord intersect at a point on a circle, then the measure of each angle formed is one half the measure of its intercepted arc".
Thus, we have;
Measure of angle = [tex]\frac{1}{2} m( \widehat{AB})[/tex]
Substituting the value, we get;
Measure of angle = [tex]\frac{1}{2} (100^{\circ}) = 50^{\circ}[/tex]
Thus, the measure of angle between the tangent l and the secant AB is 50°
Answer:
50°
Step-by-step explanation:
x + (x + 160) = 360
2x = 200
x = 100
OAB = OBA = (180 - 100)/2
= 80/2
= 40
Required angle:
90 - 40 = 50