A socce rball is kicked horizontally off a cliff with an initial speed of 8 meters per second and lands 16 meters from the base of the cliff. What is the time of flight of the soccer ball?

time of flight of a projectile motion is the time from when the object is projected to the time it gets to the surface. And itdepends on the initial velocity and the angle of the projection f the object

Along horizontal there is no acceleration. So,

Time of flight = Distance/ Time........equ(1)

Initial velocity U=0

Acceleration due to gravity g= 9.81m/s

h=ut+0.5gt^2.................eqn(2) ( vertical direction dynamic)

Time of flight= 16/8 =[tex]2m/s[/tex]

H=0+(2)+0.5(9.81)*(2)^2

H=21.62

tochinwachukwu33 tochinwachukwu33 · Answer 2 · 2020-04-12T05:13:41+02:00

Answer:

The time of flight of the soccer ball is 2 seconds.

Explanation:

For horizontal projectile motion, the equations of motion are modified to become the following.

[tex]x=u_{x}\times t[/tex]

where x is the horizontal distance covered by the object,

t = time of flight of the object

u = speed of the object.

From this it follows that

[tex]t=\frac{x}{u_{x}}=\frac{16}{8}=2seconds[/tex]

Therefore, the time of flight of the soccer ball is 2 seconds.