Heya!
We can use the extended version product rule to solve: log_p(abc) = log_p(a) + log_p(b) + log_p(c)
We can factor 60 using 2, 3, and 5.
60 = 2^2 * 3 * 5
Substitute these numbers into the rule.
log(2^2 * 3 * 5) = 2 log_p(2) + log_p(3) + log_p(5)
Using the values given in the question, we can substitute in the equation.
2 log_p(2) + log_p(3) + log_p(5) → 2(0.09) + 0.14 + 0.21
Simplify the equation.
2(0.09) + 0.14 + 0.21
0.18 + 0.14 + 0.21
0.53
Therefore, [tex]\text{log}_p(60) = 0.53[/tex]
Best of Luck!
