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In the year 2008, a company made $4.9 million in profit. For each consecutive year after that, their profit increased by 12%. How much would the company's profit be in the year 2011, to the nearest tenth of a million dollars?

Respuesta :

Answer:

The profit of the company in 2011 is $ 6.89 million

Step-by-step explanation:

Given data

In 2008 profit made by the company (P) = $ 4.9 million

Increase in profit of the company R = 12 % yearly

Now the profit of the company in 2011 is given by

[tex]P_{1} = P (1 + \frac{R}{100}) ^{T}[/tex]

Here P =  $ 4.9 million

R = 12 % = 0.12

T = 3 years

Thus  the profit of the company in 2011 is

[tex]P_{1} = 4.9 (1 + \frac{12}{100}) ^{3}[/tex]

[tex]P_{1}[/tex] = 6.89 million dollars

Therefore the profit of the company in 2011 is $ 6.89 million

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