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The total cost of placing an advertisement in a newspaper compromises of a fixed cost of $3.50 and a variable cost that depends on the number of words. Each word costs 25 cents.
1. Find the total cost of pacing an advertisement containing 22 words
2. If Michael does not want to spend more than $15 on an advertisement, what is the greatest number of words he can use?

Respuesta :

hannahhk03
1. F(x)=3.50+.25(22) which equals 9.

2. In order to find the greatest amount of words you need to have a variable representing the amount of words, its easiest to use X. In the equation I used above I put 22 in place of the X so since your trying to find the X the equation you’ll use is 15=3.50+.25(X) and solve to find X=46 words is the max he can use which will equal exactly 15 dollars. You put 15 on the other side of the equation because you need it to be equal to 15 dollars in the end.

The total cost of pacing an advertisement containing 22 word is $9.

The greatest number of words he can use is 46 words.

The total cost of placing an advertisement in a newspaper is the sum of the fixed cost and the variable cost. Fixed cost is the cost that remains constant regardless of the number of words. Variable cost is the cost that increases with the number of words.

Total cost = fixed cost + variable cost

$3.50 + $0.25w

Where:

w = number of words

The total cost of pacing an advertisement containing 22 words = $3.50 + ($0.25 x 22) = $9

Greatest number of words:  $15 = $3.50 + $0.25x

$15 - $3.50 = $0.25x

$11.50 = $0.25x

x = 46 words

To learn more about fixed costs, please check: https://brainly.com/question/25879561

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