Answer:
Approximately the volume of cone-shaped container is 393 in³.
Step-by-step explanation:
Given:
A company makes a cone-shaped container with a height of 15 in.
The area of its base is about 78.8 in².
Now, to get the cone-shaped container volume.
So, we find the radius first by using formula:
Let the radius be [tex]r.[/tex]
(Using the value π = 3.14)
[tex]A_{B}=78.8\ in^2.[/tex]
[tex]A_{B}=\pi r^2[/tex]
[tex]78.8=3.14\times r^2[/tex]
Dividing both sides by 3.14 we get:
[tex]25.09=r^2[/tex]
Using square root on both sides we get:
[tex]5.00=r[/tex]
[tex]r=5\ in.[/tex]
Thus, the radius ([tex]r[/tex]) = 5 in.
The height ([tex]h[/tex]) = 15 in.
Now, to get the volume of the cone-shaped container we put formula:
[tex]Volume=\pi r^2\frac{h}{3}[/tex]
[tex]Volume=3.14\times 5^2\times \frac{15}{3} \\\\Volume=3.14\times 25\times 5\\\\Volume=392.50\ in^3.[/tex]
Therefore, approximately the volume of the cone-shaped container is 393 in³.
