Respuesta :
Answer:
a) Excitation energy for the third excited state = -112 eV
b) The amount of energy required to cause an object in the third excited state to become unbound = 112 eV
c) Max number of photons emitted as the object de - excites from the third excited state to the ground state = 6
d) Maximum wavelength photons = 532.286 nm
Minimum wavelength photons = 59.14 nm
Explanation:
From the question, the energy levels are given by [tex]E_{n} = E_{1} n[/tex]
Where the energy level for the ground state is given by [tex]E_{1} = -28.0 eV[/tex]
a) Excitation energy for the third excited state, n = 4
[tex]E_{4} = 4 * E_{1}[/tex]
[tex]E_{4} = -28 * 4[/tex]
[tex]E_{4} = -112 eV[/tex]
b) The amount of energy required to cause an object in the third excited state to become unbound
[tex]E_{4} = 112 eV[/tex]
c) Max number of photons emitted = [tex]\frac{n(n-1)}{2}[/tex]
Max number of photons emitted = [tex]\frac{4(4-1)}{2}[/tex]
Max number of photons emitted = 2 * 3 = 6
d) [tex]\frac{1}{\lambda_{max} } = \frac{28}{hc} [\frac{1}{3} -\frac{1}{4}][/tex]
[tex]hc = 1242 eV-nm[/tex]
[tex]\frac{1}{\lambda_{max} } = \frac{28}{1242} [\frac{1}{3} -\frac{1}{4}][/tex]
[tex]\lambda_{max} = 532.286 nm[/tex]
Maximum wavelength photons = 532.286 nm
[tex]\frac{1}{\lambda_{min} } = \frac{28}{hc} [\frac{1}{1} -\frac{1}{4}][/tex]
[tex]\frac{1}{\lambda_{min} } = \frac{28}{1242} [\frac{1}{1} -\frac{1}{4}][/tex]
[tex]\lambda_{min} = 59.14 nm[/tex]
Minimum wavelength photons = 59.14 nm
