Respuesta :
Answer:
mass of CO_2 formed=[tex]0.75\times 44g =33 g[/tex]
Explanation:
First balance the chemical reaction:
[tex]CH_4 +2O_2 \rightarrow CO_2 +2H_2O[/tex]
molecular mass of [tex]CH_4=16g/Mol[/tex]
molecular mass of [tex]O_2=32g/Mol[/tex]
mass given of [tex]CH_4=12g[/tex]
mole of [tex]CH_4=12/16mol=0.75mol[/tex]
mass given of [tex]O_2=133g[/tex]
mole of [tex]O_2=133/32mol=4.16 mol[/tex]
from the above balanced equation:
1 mole of [tex]CH_4[/tex] need 2 mole of [tex]O_2[/tex] gas
therefore 0.75 mole of [tex]CH_4[/tex] will react with 1.5 mole of [tex]O_2[/tex] only
but we have 4.16 mole [tex]O_2[/tex] gas
hence [tex]O_2[/tex] will be the excess reagent and [tex]CH_4[/tex] will be the limiting eagent so production of [tex]CO_2[/tex] will depenf on the quantity of limiing reagent i.e. [tex]CH_4[/tex]
from the above balanced equation:
1 mole of [tex]CH_4[/tex] gives 1 mole of [tex]CO_2[/tex] on complete reacion with [tex]O_2[/tex]
hence,
0.75 mole of [tex]CH_4[/tex] gives 0.75 mole of [tex]CO_2[/tex] on complete reacion with [tex]O_2[/tex]
mass of CO_2 formed=[tex]0.75\times 44g =33 g[/tex]
