The equation that is correct regarding the diagram of Circle O is; m∠XOY = One-half(a – b)
From the cyclic angle theorem, we know that the angle at the vertex is equal to half of the difference of its intercepted arcs.
We are given;
m<XOY
arc A
arc B
Difference of intercepted arcs = (arc b - arc d)
Thus, applying the theorem above is;
m∠XOY = One-half(a – b)
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