Respuesta :

Given:

Sides of a triangle are

a = 3 in, b = 4 in and c = 5 in

To find:

The area of the triangle.

Solution:

Using Heron's formula:

[tex]$S=\frac{a+b+c}{2}[/tex]

[tex]$S=\frac{3+4+5}{2}[/tex]

S = 6 in

[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]

[tex]A=\sqrt{6(6-3)(6-4)(6-5)}[/tex]

[tex]A=\sqrt{6(3)(2)(1)}[/tex]

[tex]A=\sqrt{36}[/tex]

[tex]A=6[/tex] in²

Area of a triangle is 6 in².

Given:

Given that the sides of the triangle are 3 inches, 5 inches and 4 inches.

We need to determine the area of the triangle.

Area of the triangle:

The area of triangle can be determined using the formula,

[tex]A=\frac{1}{2}bh[/tex]

where b is the base of the triangle and h is the height of the triangle.

From the figure, it is obvious that the base of the triangle is 4 inches and the height of the triangle is 3 inches.

Substituting b = 4 and h = 3 in the above formula, we get;

[tex]A=\frac{1}{2}(4)(3)[/tex]

[tex]A=\frac{1}{2}(12)[/tex]

[tex]A=6[/tex]

Thus, the area of the triangle is 6 square inches.

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