Respuesta :
Answer:
Option A is correct.
Bug A is experiencing a greater radial acceleration than Bug B.
Explanation:
The two bugs have the same angular speed, w, but different radii of the circular motion.
Bug A is closer to the edge of the turntable and bug B is farther from the edge of the turntable.
Hence, Bug A has a bigger radius of circular motion, hence, its radius can be called R and the radius of the circular motion for bug B is r.
v = wr
The radial acceleration of a body in circular motion is given as
α = (v²/r) = rw²
Radial acceleration for bug A = Rw²
Radial acceleration for bug B = rw²
Since we established that R > r and the angular speeds are equal,
Rw² > rw²
Hope this Helps!!!
Answer:
The answer is: f. Bug B is experiencing a greater radial acceleration than Bug A.
Explanation:
The radial acceleration is equal to:
[tex]a_{c} =\frac{v^{2} }{r}[/tex]
If the radial velocity is:
[tex]v=rw[/tex]
Replacing:
[tex]a_{c} =\frac{(rw)^{2} }{r} =w^{2} r[/tex]
According the problem w is the same for both A and B and r is the distance from center, then:
[tex]r_{B} >r_{A}[/tex]
According to this expression, it can be concluded that:
[tex]a_{c,B} >a_{c,A}[/tex]
