Respuesta :

dalendrk
[tex]A=\dfrac{a+b}{2}\cdot h\\\\a=29.2\ in.\\b=20\ in.\\h=12.5\ in.\\\\subtitute\\\\A=\dfrac{29.2+20}{2}\cdot12.5=\dfrac{49.2}{2}\cdot12.5=24.6\cdot12.5=307.5\ (in.^2)[/tex]
JeanaShupp

Answer: [tex]307.5\ in.^2[/tex]

Step-by-step explanation:

The area of trapezoid is given by :-

[tex]\text{Area}=\dfrac{1}{2}(a+b)h[/tex], where a and b area the bases and h is height of the trapezoid.

Given: The length of the bases are 20 in. and 29.2 in. cm.

The height of the trapezoid = 12.5 in.

Now, the area of a trapezoid will be:-

[tex]\text{Area}=\dfrac{1}{2}(20+29.2)(12.5)\\\\\Rightarrow\text{Area}=307.5\ in.^2[/tex]

Hence, the area of a trapezoid  = [tex]307.5\ in.^2[/tex]

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