Four friends were born in consecutive years. The sum of their ages is 94. What is the age of the oldest friend?

Hello,

We don't need algebra to solve this.

I suppose the ages are 1,2,3,4
Their sum is 1+2+3+4=10.
To obtain 94 we must add 94-10=84 for 4 persons =>84/4=21 to each

Ages are
1+21=22
2+21=23
3+21=24
4+21=25

But if really want an algebric resolution:

Let's x the age of the youngest
x+1,x+2,x+3 the others.

x+(x+1)+(x+2)+(x+3)=94
==>4x+6=94
==>4x=88
==>x=22
Ages are 22,23,24,25.

The oldest friend is 25 years old.

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JeanaShupp JeanaShupp · Answer 2 · 2019-03-19T18:55:25+01:00

JeanaShupp JeanaShupp

19-03-2019

Answer: 25 years

Step-by-step explanation:

Let x, x+1, x+2, x+3 are the ages of four friends which were born in consecutive years.

Now, according to the question

[tex]x+(x+1)+(x+2)+(x+3)=94\\\\\Rightarrow4x+6=94\\\\\Rightarrow4x=94-6\\\\\Rightarrow4x=88\\\\\Rightarrow\ x=\frac{88}{4}\\\\\Rightarrow\ x=22[/tex]

Now, the age of the oldest friend [tex]= x+3=22+3=25\text{ years}[/tex]

Hence, the age of the oldest friend is 25 years.

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