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The density of gold is approximately 19.2 g/cm3. What is the mass of a sample of gold that displaces 20.0 cm3 of water? Round your answer to the correct number of significant figures.

Respuesta :

Willchemistry
Density = 19.2 g/cm³

Volume = 20.0 cm³

Mass = ?

D = m / V

19.2 = m / 20.0

m = 19.2 x 20.0

m = 384.0 g

hope this helps!

Answer:

384.0 grams is the mass of a sample of gold that displaces 20.0 [tex]cm^3[/tex] of water.

Explanation:

Density of gold = [tex]d=19.2 g/cm^3[/tex]

Volume of water displaced gold = [tex]20.0 cm^3[/tex]

Volume of water displaced is equal to the volume occupied by the gold sample.

Volume of the gold , v = [tex]20.0 cm^3[/tex]

[tex]Density =\frac{Mass}{Volume}[/tex]

Mass of gold :

[tex]Density\time Volume =19.2 g/cm^3\times 20.0 cm^3= 384.0 g[/tex]

Mass of gold = 384.0 g

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