Respuesta :
add them together
2x-4=0
2x=4
x=2
2-y=0
y=2
(2,2)
in quadrant 1
2x-4=0
2x=4
x=2
2-y=0
y=2
(2,2)
in quadrant 1
We may add the equations to find the value of the x first,
x + y = 4
+ x - y = 0
The sum would be 2x = 4 which gives the value of x as 2. Substitute this value to any of the equations to solve for y. The value of y is 2. Thus, the solution of the system is (2, 2) which is in the Quadrant 1.
x + y = 4
+ x - y = 0
The sum would be 2x = 4 which gives the value of x as 2. Substitute this value to any of the equations to solve for y. The value of y is 2. Thus, the solution of the system is (2, 2) which is in the Quadrant 1.