A. The weight of the sled is the product of its mass and the acceleration due to gravity,
(50 kg) x (9.81 m/s²) = 490 N
B. The force needed is the product of static friction coefficient and the normal which is equal to the weight,
F = (490 N) x 0.30 = 147 N
C. The force is the product of the sliding friction coefficient and the normal force,
F = (490) x (0.10) = 49 N
D. The net force is calculated as,
Fnet = ma = F - 49 N
Substituting the values,
(50 kg) x (3.0 m/ s²) = F - 49 N
The value of F is approximately equal to 199 N.