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a squirrel happens on a hidden lair of nuts. it decides to make the most of it by doubling the amount of nuts during the day and eat two nuts in the evening. by nightfall of the 3rd day there were 34 nuts in the lair. how many nuts were in the original found treasure? 6 10 12 8

Respuesta :

Edufirst
initial amount of nuts = x

at the end of first day (including the night): 2x - 2
at the end of second day (including the night): 2(2x-2) -2 = 4x - 4 - 2 = 4x - 6
at the end of second day (including the night): 2 [4x -6] - 2 = 8x - 12 - 2 = 8x - 14

8x - 14 = 34

x = [34 +14]/8 = 48/8 = 6

Answer: 6

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