Answer:
The distance between any two corresponding points is 5 unit.
Step-by-step explanation:
Let (x,y) represents the coordinates of the triangle xyz,
Thus, after translation translated 4 units up and 3 units left,
[tex](x,y)\rightarrow (x+3,y+4)[/tex]
That is, if triangle x'y'z' is the resultant figure after translation,
Then (x+3,y+4) represents the coordinates of triangle x'y'z',
By the distance formula,
The distance between any two corresponding points of triangle xyz and x'y'z',
[tex]d=\sqrt{(x+3-x)^2+(y+4-y)^2}[/tex]
[tex]=\sqrt{3^2+4^2}[/tex]
[tex]=\sqrt{9+16}[/tex]
[tex]=\sqrt{25}[/tex]
[tex]=5\text{ unit}[/tex]
