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A 25-mL sample of 0.160M solution of NaOH is titrated with 17 mL of an unknown solution of
H2
SO4
. What is the molarity of the sulfuric acid solution?
A. 0.235M H2
SO4
B. 0.117M H2SO4
C. 0.004M H2
SO4
D. 0.002M H2SO4

Respuesta :

Willchemistry
V ( NaOH ) = 25 mL in liters : 25 / 1000 => 0.025 L

M ( NaOH ) = 0.160 M

V ( H2SO4) = 17 mL / 1000 => 0.017 L

M ( H2SO4) = ?

number of moles NaOH:

n = M x V = 0.160 x 0.025 => 0.004 moles NaOH

Mole ratio :

2 NaOH + H2SO4 = Na2SO4 + 2 H2O

2 moles NaOH ----------- 1 mole H2SO4
0.004 moles NaOH ----- ? moles H2SO4

moles H2SO4 = 0.004 x 1 / 2

= 0.002 moles of H2SO4

M ( H2SO4) = n / V

M = 0.002 / 0.017

 = 0.117 M H2SO4

Answer B

hope this helps!

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