Respuesta :
[tex]2x^2-7x=3\\2x^2-7x-3=0\\\\a=2;\ b=-7;\ c=-3\\\Delta=b^2-4ac\\\\\Delta=(-7)^2-4\cdot2\cdot(-3)=49+24=73 \ \textgreater \ 0\\\\therefore\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{7-\sqrt{73}}{2\cdot2}=\boxed{\dfrac{7-\sqrt{73}}{4}\approx-0.39}\\\\x_2=\dfrac{7+\sqrt{73}}{2\cdot2}=\boxed{\dfrac{7+\sqrt{73}}{4}\approx3.89}[/tex]