boyygirlmsnh
contestada

When looking at a rational function, Charles and Bobby have two different thoughts. Charles says that the function is defined at x = -2, x = 3, and x = 5. Bobby says that the function is undefined at those x values. Describe a situation where Charles is correct, and describe a situation where Bobby is correct. Is it possible for a situation to exist that they are both correct? Justify your reasoning.

Respuesta :

apologiabiology
charles funcion
it is any function without (x+2)(x-3)(x-5) in the deonmenator
so it can be like
f(x)=3x+4

dividing by zero is undefined so
f(x)=[tex] \frac{1}{(x+2)(x-3)(x-5)} [/tex] would be a place where the function is undefined at x=-2,x=3 and x=5



charles: f(x)=3x+4
bobby: f(x)=[tex] \frac{1}{(x+2)(x-3)(x-5)} [/tex]
there is no function where both are correct, it cannot be both defined and undefined


Otras preguntas