the work of a student to solve a set of equations is shown: equation a: y = 15 − 2z equation b: 2y = 3 − 4z step 1: −2(y) = −2(15 − 2z) [equation a is multiplied by −2.] 2y = 3 − 4z [equation b] step 2: −2y = 15 − 2z [equation a in step 1 is simplified.] 2y = 3 − 4z [equation b] step 3: 0 = 18 − 6z [equations in step 2 are added.] step 4: 6z = 18 step 5: z = 3 in which step did the student first make an error? step1 step 2 step 3 step 4

If you would like to solve a set of equations, you can do this using the following steps:

equation a: y = 15 - 2z /*(-2)
equation b: 2y = 3 - 4z
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-2y = (-2) * (15 - 2z)
-2y = -30 + 4z
2y = 3 - 4z

The mistake was made at step 2: −2y = 15 − 2z [equation a in step 1 is simplified.]. The correct simplification would be -2y = -30 + 4z.

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vintechnology vintechnology · Answer 2 · 2022-05-25T12:07:29+02:00

The step the student makes the error is in step 1 . The correct answer when you multiply equation(i) by -2 is -2y = -30 + 4z

How to find the variables in a system of equation?

y = 15 − 2z

2y = 3 − 4z

The mistake was made in step 1. let's multiply equation(i) by -2 to see the final value.

-2(y) = -2(15 - 2z)

open the bracket

-2y = -30 + 4z

The multiplication of -2 by the first equation result to -2y = -30 + 4z

learn more on system of equation here: brainly.com/question/19549073

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