Answer : Resistance of a clock is [tex]30\ \Omega[/tex].
Explanation :
It is given that :
The current flowing in the clock, I = 0.3 A
Potential difference, V = 9 V
According to Ohm's law :
[tex]V=I\times R[/tex]
So,
[tex]R=\dfrac{V}{I}[/tex]
[tex]R=\dfrac{9\ V}{0.3\ A}[/tex]
[tex]R=30\ \Omega[/tex]
[tex]\Omega[/tex] is the SI unit of the resistance given by a physicist Georg Simon Ohm.
So, the correct option is (d) i.e. [tex]30\ \Omega[/tex]
Hence, this is the required solution.
