Answer:
The vertices of coordinates of image are Q'(0,-4), P'(-7,-6) and R'(-1,-2).
Step-by-step explanation:
The vertices of triangle QPR are Q(–4,0), P(–6, 7), and R(–2, 1). It is rotated 90° counterclockwise about the origin to form a new triangle Q'P'R'.
If a figure rotated 90° counterclockwise about the origin, then
[tex](x,y)\rightarrow (-y,x)[/tex]
The coordinated of image are
[tex]Q(-4,0)\rightarrow Q'(0,-4)[/tex]
[tex]P(-6,7)\rightarrow P'(-7,-6)[/tex]
[tex]R(-2,1)\rightarrow R'(-1,-2)[/tex]
Therefore the vertices of coordinates of image are Q'(0,-4), P'(-7,-6) and R'(-1,-2).
