The kinetic energy of flywheel of a stationary engine is 120J.
Explanation:
Key Terms:
- torque: A rotational or twisting effect of a force; (SI unit newton-meter or N m; imperial unit foot-pound or ft-lb)
- inertia: The property of a body that resists any change to its uniform motion; equivalent to its mass.
- angular velocity: A vector quantity describing an object in circular motion; its magnitude is equal to the speed of the particle and the direction is perpendicular to the plane of its circular motion.
Here , angular acceleration = 2 [tex]rads^{-2}[/tex]
Angular velocity w = Angular acceleration × time
∵ Acceleration is 2 rad per second sq. So , time is 1 sec.
⇒ Angular velocity (w) = [tex]2(1)[/tex]
⇒ Angular velocity (w) = [tex]2\frac{rad}{s}[/tex]
[tex]E_r_o_t_a_t_i_o_n_a_l = \frac{1}{2} Iw^{2}[/tex]
Now, kinetic energy ⇒ [tex]E_r_o_t_a_t_i_o_n_a_l = \frac{1}{2} Iw^{2}[/tex]
⇒ [tex]E_r_o_t_a_t_i_o_n_a_l = \frac{1}{2} Iw^{2}[/tex]
⇒ [tex]E_r_o_t_a_t_i_o_n_a_l = \frac{1}{2} (60)2^{2}[/tex]
⇒ [tex]E_r_o_t_a_t_i_o_n_a_l = 120J[/tex]
∴ The kinetic energy of flywheel of a stationary engine is 120J.
