Answer:
[tex]\large \boxed{8.100 \times 10^{4} \text{ Pa}}[/tex]
Explanation:
[tex]\text{Pressure} = \text{23.92 inHg} \times \dfrac{\text{2.54 cmHg}}{\text{1 inHg}} \times \dfrac{\text{1 atm}}{\text{76 cmHg}} \times \dfrac{\text{101.325 kPa}}{\text{1 atm}} = \text{ 81.00 kPa}\\\text{The pressure is $\large \boxed{\mathbf{8.100 \times 10^{4}} \textbf{ Pa}}$}[/tex]
