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Two planes take off at a New York airport.The first plane climbs at an angle of 45 with respect of the ground and reaches an altitude of 5600 feet.the second plane climbs at an angle of 60with respect to the ground and reaches an altitude of 8200 feet.to the nearest foot which plane covers a longer ground distance

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Answer:

The second plane climbs at an angle of 60 with respect to the ground and reaches an altitude of 8200 rounded feet. This means his angle is larger so therefore his distance is larger by 1/3 per 45 degree the formula for speed, s = d/t which means speed equals distance divided by time. if 45 is 1/2 then 60 is the new 1/3 size that covers a greater distance. As s=d/t.

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