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What is the equation of a line l that has an x-intercept of (5, 0) and is perpendicular to another line m that has a slope -5?
Question 14 options:


y = -5x+ 25


y= -5x + 5


y = 1/5 x + 5


y = 1/5 x - 1

Respuesta :

ammarsani9

Answer:

[tex]y=\frac{1}{5}x+5[/tex]

Step-by-step explanation:

Slope of a perpendicular line is the "negative reciprocal" of the slope of the original line (i.e [tex]m=-5[/tex])

∴  [tex]m=-\frac{1}{-5}=\frac{1}{5}[/tex]

the slope-intercept form: [tex]y=mx+c[/tex]

with

[tex]m=\frac{1}{5}[/tex]

and [tex]c=5[/tex]

is

[tex]y=\frac{1}{5}x+5[/tex]