Help normal distributions
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Answer:
0.0215
Step-by-step explanation:
The average weekly wage is $400 and the standard deviation is:
$50
The z-score for $250 is given by:
[tex]z = \frac{x - \mu}{ \sigma} [/tex]
Plug in the values to get:
[tex]z = \frac{250 - 400}{ 50} = - 3[/tex]
The z-score of $300 is
[tex]z = \frac{300 - 400}{ 50} = - 2[/tex]
The probability of earning less than:
$250 is
P(X<250)=0.0013, we got this by reading -3 under zero on the standard normal distribution table.
Similarly:
P(X<300)=0.0228
P(250<X<300)=0.0228-0.0013=0.0215
Therefore the probability that a workeep makes between 250 and 300 dollars is 2.15%