Answer:
Step-by-step explanation:
Yes, because the limit on the left and the limit on the right is equal to the value at a given point.
[tex]\lim\limits_{x\to9^-}f(x)=\lim\limits_{x\to9^+}f(x)=f(9)[/tex]
[tex]f(x)=3x-9\\\\\lim\limit_{x\to9^-}(3x-9)=3(9)-9=27-9=18\\\\\lim\limit_{x\to9^+}(3x-9)=3(9)-9=27-9=18\\\\f(9)=3(9)-9=27-9=18[/tex]