Answer:
[tex]\huge\boxed{x=-\dfrac{1}{5}=-0.2}[/tex]
Step-by-step explanation:
[tex]x-\text{the number}\\\\5\cdot x=5x-\text{the product of a number and 5}\\\\5x+9-\text{nine more than the product of a number and 5}\\\\\text{The equation:}\\\\5x+9=8\\\\\text{Solution:}\\\\5x+9=8\qquad\text{subtract 9 from both sides}\\\\5x+9-9=8-9\\\\5x=-1\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{-1}{5}\\\\x=-\dfrac{1}{5}[/tex]
