Hello! don't forget to write complete questions in order to get good and exact answers. You haven't provided any table, so I'll assume this one:
[tex]\begin{array}{cc}x(seconds) & y(meters)\\0 & 0\\1 & 10\\2 & 20\end{array}[/tex]
The speed of this can is the slope of the line given by the table, therefore:
[tex]s_{B}:\text{speed of car B} \\m:slope\\ \\ \\s_{B}=m=\frac{10-0}{1-0}=10m/s[/tex]
From the table, we know that the line passes through the origin, so the equation is:
[tex]y=10x[/tex]
For car A, we know that the speed is also the slope of that line, so:
[tex]S_{A}:\text{Speed of car A} \\ \\ s_{A}=m=6m/s[/tex]
By comparing these two values, we can conclude that:
Car b is faster by 4 meters per second
