idk102332814 idk102332814

15-03-2020
Chemistry

contestada

at constant atmospheric pressure, the temperature of a gas that occupies the volume of 5.30 L is 298 K. what is the temperature of the gas if it is allowed to expand to 7.60 L?

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magalieisik magalieisik

16-03-2020

Answer:

The new temperature of the gas is 427K

Explanation:

In this case we use Charles's Law according to which the volume and temperature of a certain amount of gas are related, keeping the pressure constant.

V1 / T1 = V2 / T2

5,30L/298K=7,60L/T2

T2=7,60L/(5,30L/298K)=427,32K

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