On a coordinate plane, a line F G goes through (negative 8, negative 8) and (8, 4). Point H is at (6, negative 6).
Which point is on the line that passes through point H and is perpendicular to line FG?

(–6, 10)
(–2, –12)
(0, –2)
(4, 2)

Respuesta :

Answer:

(–6, 10)

Step-by-step explanation:

Because the line is perpendicular its slope is the negative reciprocal of line FG. If we examine the graph and plot out the slope we see that it crosses point (–6, 10).

The slope of a line perpendicular to line FG can be found by changing the

sign and inverting the value of the slope of the line  FG.

The point on the perpendicular line passing through point H is [tex]\underline{(-6, \ -10)}[/tex]

Reasons:

The given points on the line FG are; (-8, -8), (8, 4), and H(6, -6)

Required:

The point on the perpendicular line passing through point H and is

perpendicular to FG.

Solution:

The slope of a line, perpendicular to another line that has a slope m, is [tex]-\dfrac{1}{m}[/tex]

The slope, m, of the line FG is found as follows;

[tex]Slope, \, m =\dfrac{4-(-8)}{8-(-8)} = \dfrac{12}{16} = \dfrac{3}{4}[/tex]

Therefore, the slope of the perpendicular line is [tex]-\dfrac{4}{3}[/tex]

The numerator and the denominator of the perpendicular line have the

different signs, therefore, by checking point (-6, -10), we have;

[tex]Slope =\dfrac{10-(-6)}{-6-6} = -\dfrac{16}{12} = -\dfrac{4}{3}[/tex]

Therefore;

The point on the perpendicular line passing through point H is [tex]\underline{(-6, \ -10)}[/tex]

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