Answer:
[tex](G(s(z)))'=G'(s(z))\cdot s'(z))[/tex]
Step-by-step explanation:
If G is a function of s, and s is a function of z, then the composition function is :
[tex](G\circ s)(z)=G(s(z))[/tex]
This is a function of a function. So we apply the chain rule to different the outer function multiply by the derivative of the inner function.
We take the first derivative to obtain:
[tex](G(s(z)))'=G'(s(z))\cdot s'(z))[/tex]
