There are thirty-five red, yellow, orange, and white marbles in a bag. If half the number of red marbles equals two less than the number of yellow marbles, equals a third the number of orange marbles, and equals a third of three more than the number of white marbles, how many red marbles are there?

Respuesta :

Answer:

8 red

Step-by-step explanation:

r/2 = y - 2 = ⅓ × o = (w+3)/3

r + y + o + w = 35

r = 8, y = 6, o = 12, w = 9

Answer:

There are 8 red marbles

Step-by-step explanation:

Let the number of red be R , number of yellow be Y , number of orange be O and number of white be W. Then

[tex]R+Y+O+W=35[/tex] ..................... *

Half the number of red implies : [tex]\frac{R}{2}[/tex]

Two less than the number of yellow implies : [tex]y-2[/tex]

A third the number of orange implies : [tex]\frac{O}{2}[/tex]

A third of three more than the number of white marbles implies : [tex]\frac{1}{3}(W+3)[/tex]

combining everything together , we have

[tex]\frac{R}{2}=Y-2=\frac{O}{2}=\frac{1}{3}(W+3)[/tex]

[tex]\frac{R}{2}=Y-2[/tex]  implies : [tex]R = 2(Y-2)=2Y-4[/tex] ................ equation 1

[tex]Y-2=\frac{O}{2}[/tex] implies : [tex]2(Y-2) = O[/tex]

therefore: [tex]O = 2Y-4[/tex] ...................... equation 2

[tex]Y-2 = \frac{1}{3}(W+3)[/tex] implies : [tex]3(Y-2)=W+3[/tex]

[tex]3Y-6=W+3[/tex]

Therefore: [tex]W=3Y-9[/tex] ......................... equation 3

Substituting equation 1 ,2 and 3 into equation * , we have

[tex]2Y-4+Y+3Y-6+3Y-9=35[/tex]

[tex]9Y-19=35[/tex]

[tex]9Y=35+19[/tex]

[tex]9Y=54[/tex]

[tex]Y=54/9[/tex]

[tex]Y=6[/tex]

substitute the values of Y , to get R , O and W

[tex]R=2Y-4[/tex]

[tex]R=2(6)-4[/tex]

[tex]R=12-4[/tex]

[tex]R=8[/tex]

[tex]O=3Y-6[/tex]

[tex]O=18-6[/tex]

[tex]O=12[/tex]

[tex]W=3Y-9[/tex]

[tex]W=18-9[/tex]

[tex]W=9[/tex]

Therefore:

number of red = 8

number of yellow = 6

number of orange = 12

number of white = 9