Answer:
1. CH3COOH + NaHCO3 —> CH3COONa + H2O + CO2
2. Double Displacement and Decomposition reaction.
Explanation:
1. The balanced equation for the reaction is given below:
CH3COOH + NaHCO3 —> CH3COONa + H2O + CO2
2. There are actually two types of reactions that occur in the reaction between acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3)
The first is a DOUBLE DISPLACEMENT reaction in which the acetic acid react with the bicarbonate to form sodium acetate and carbonic acid as shown below:
CH3COOH + NaHCO3 —> CH3COONa + H2CO3
The second type of reaction is DECOMPOSITION REACTION. The carbonic acid (H2CO3) form is unstable and will decompose to form H2O and CO2 as shown below:
H2CO3 —> H2O + CO2
