Answer:
88 g of CO₂ were produced by this reaction
Explanation:
We determine the combustion:
C(s) + O₂(g) → CO₂(g)
If the problem states, that oxygen has remained after the reaction is complete, the O₂ is the excess reactant and the limiting.
We convert mass to moles → 24 g . 1mol / 12g = 2 moles
As ratio is 1:1, 2 moles of C must produce 2 moles of CO₂
We convert the moles to mass:
2mol . 44g/ 1mol = 88 g
