A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 32.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

Respuesta :

Answer:

Average force exerted by the water on the blades is 1024 N

Explanation:

As we know that the force due to water jet is given by

[tex]F = (v_{in} - v_{out})\frac{dm}{dt}[/tex]

here we know that

[tex]v_{in} = 16 m/s[/tex]

[tex]v_{out} = -16 m/s[/tex]

[tex]\frac{dm}{dt} = 32 kg/s[/tex]

so here we will have

[tex]F = (16 + 16)(32)[/tex]

[tex]F = 1024 N[/tex]

Average force exerted by the water on the blades is 1024 N