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A capacitor in an RC circuit with R = 2 Ω and C = 4 F is being charged. The time required for the capacitor voltage to reach 63.2 percent of its steady-state value is: Group of answer choices 2 s 4 s 8 s 16 s

Respuesta :

Given Information:

Resistance = R = 2 Ω

Capacitance = C = 4 F

Required Information:

Time constant = τ = ?

Answer:

τ = 8 seconds

Explanation:

one time constant τ is the amount of time taken when the capacitor chargers up to approximately 63 % of its maximum possible voltage.

τ = RC

τ = 2*4

τ = 8 seconds

So that means after 1 τ (8 seconds) the capacitor voltage will reach approximately 63.2 % of its maximum possible voltage.

Cricetus

The time required for the capacitor voltage will be "8 seconds".

Given values are:

  • Resistance, R = 2 Ω
  • Capacitance, C = 4 F

As we know the formula,

→ Time taken, [tex]\tau = RC[/tex]

By substituting the above values, we get

                          [tex]= 2\times 4[/tex]

                          [tex]= 8 \ seconds[/tex]

Thus the above response i.e., "option c" is right.

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