Answer: [tex]\frac{9}{64}[/tex]
Step-by-step explanation:
n(gold colored coins) = 10
n(silver colored coins) = 6
Total number of coins = 16
since there is replacement , the probability she selects 2 silver colored coins will be :
[tex]\frac{6}{16}[/tex] x [tex]\frac{6}{16}[/tex]
= [tex]\frac{3}{8}[/tex] x [tex]\frac{3}{8}[/tex]
= [tex]\frac{9}{64}[/tex]
Therefore : the probability she selects 2 silver colored coins is [tex]\frac{9}{64}[/tex]
Answer:
Step-by-step explanation:
p=number of silver coins/total number of coins
p=3/8 of 3/8=9/64
