Answer:
Mole fraction ethyl acetate → 0.52
Explanation:
Determine the solution's compound:
Solute: Ethyl-acetate (C₄H₈O₂), molar mass = 88 g/mol
Solvent: Toluene (C₇H₈), molar mass = 92 g/mol
We have density of each, so let's determine their masses:
Density = Mass / volume → Density . volume = Mass
0.898 g/mL . 1mL = 0.898 g of ethyl acetate
0.867 g/mL . 1mL = 0.867 g of tolue
We convert the mass to moles
0.898 g . 1 mol / 88 g = 0.0102 moles of ethyl acetate
0.867 g . 1mol / 92 g = 9.43×10⁻³ moles of tolulene
Mole fraction = Moles of x / Total moles
Mole fraction ethyl acetate = Moles of etyhyl acetate / Total moles
Total moles = 0.0102 + 9.43×10⁻³ = 0.01963
Mole fraction ethyl acetate = 0.0102 / 0.01963 → 0.52
The mole fraction of ethyl acetate in the mixture is 0.515 .
Volume of ethyl acetate = 1 mL
Density of ethyl acetate = 0.898 g/mL
Mass of ethyl acetate = 1 mL × 0.898 g/mL = 0.898 g
Molar mass of ethyl acetate = 88 g/mol
Number of moles of ethyl acetate = 0.898 g/88 g/mol = 0.01 moles
Volume of toluene = 1 mL
Density of toluene = 0.867 g/mL
Mass of toluene = 1 mL × 0.867 g/mL = 0.867 g
Molar mass of toluene = 92 g/mol
Number of moles of toluene = 0.867 g/ 92 g/mol = 0.0094 moles
Total number of moles = 0.01 moles + 0.0094 moles = 0.0194 moles
Mole fraction of ethyl acetate = 0.01 moles/0.0194 moles
= 0.515
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