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PLZ HELP, GIVING BRAINLIEST!!
A student prepares a solution of glucose ( C6H12O6 ) by dissolving 180.0 g of the sugar in enough water to make a 500.0 mL solution. How would the student properly label this solution?
A. 180.0 M C6H1206
B. 180.0 g/500 mL C6H12O6
C. 2.000 M C6H12O6
D. 1.000 M C6H12O6

Respuesta :

Eduard22sly

Answer:

C. 2.000 M C6H12O6

Explanation:

Let us obtain the molarity of the solution.

Molar Mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

Mass of C6H12O6 = 180g

Number of mole = Mass /Molar Mass

Number of mole of C6H12O6 = 180/180 = 1mole

Volume = 500mL = 500/1000 = 0.5L

Molarity = mole /Volume

Molarity = 1/0.5

Molarity = 2M

So the solution will be best labelled as 2M C6H12O6

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